If it's not what You are looking for type in the equation solver your own equation and let us solve it.
Oblicz to!
2-((2*x)/5) = x/3-4
2;3;5;7
((1/10)*x^1)/10 = 0
2*(cos(x))^2-1
2*(cos(x))^2
| 2-2x/5=x/3-4 | | 5x+3y-2x-y= | | 1/10x1/10 | | 4y+12y=36 | | 4a^2-6a-27=0 | | q+(-5)3=8 | | log(x)8=0.5 | | f-4-5=-9 | | Y=2.0+5.2x | | x^2-4x+y^2=32 | | 33=4v-11 | | n-8/2=11 | | (2y^2-10y+44)=(y^2-14y+49) | | 4x-2x=20-2x | | 32-5m=25 | | (8x/15a)/(2x^3/3ax) | | 8u^6+32u^5+32u^4=0 | | 10x-8x^3= | | 2u^4+21u^3+27u^2=0 | | 9p=9+p | | 10x-9=4x+6 | | 10x+5y+170=1200 | | 5x-3=2(x+7) | | 10x+5y=1200 | | -3(6f-9)= | | 5x^2+38x+16=0 | | 3x(7-x)= | | 90x-100=8x-200 | | 6y^2+x-36y+55=0 | | 2y^2=-4x+5 | | 2x^1/2-5x1/4=3 | | 6x-1=4x+2 |